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It should have been a draw, right?

I just play a hyperbullet game in which my time expired, here is the game:

tr.lichess.org/somuLngo/black#75

He has only a bishop, which means the game should be draw under normal conditions; but it became a lost for me

Do I miss something? What is the point?
He can still checkmate if your pawns block your king's escape in some way.
If black moves his king to h1, white moves his king to f1, black moves his pawn up to h2 while white waits, then Bf3 is mate for white. Therefore, white can still win the game. Therefore, if you lose on time, you lose for real.
While a checkmate with a bishop and king versus a lone king is impossible, a checkmate with a bishop and king versus a king with some other material on the board is possible. For example, a pawn can block a dark square from the black king that a light squared bishop cannot.

While in this position it is overwhelmingly in black's favor, it remains that it is possible to lose (no matter how silly it seems).
Small inaccuracy in the above post: K+B v K+R cannot be won by the bishop side at all. How that one's adjudicated on lichess when the R side runs out of time, I'm not sure.
Step 1: sac your rook and h-pawn, and promote your a and g pawns to bishops

Step 2: Put your king in a light corner

Step 3: Put your bishops orthogonally adjacent to your king

Your opponent moves his bishop to the same diagonal your king is on and BOOM! Checkmate!
@ Illion: K+B vs K+B is drawn if both bishops are of the same colour. K+B cannot win against K+Q. K+N can lose against K+B though (in a position that's almost retroanalysable), and hence any K+any pawn can lose against K+B.
K+Q probably cannot lose to K+N.

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